Find fundamental solutions, y1(t),y(t), of the differential equation y+4y+4y=0 y1(t)=te2t,y2(t)=e2ty1(t)=e2t,y2(t)=e2ty1(t)=e4t,y2(t)=te4ty1(t)=te4t,y2(t)=e4ty1(t)=e2t,y2(t)=te2t None of the options displayed. y1(t)=e2t,y2(t)=2e2t

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