Find the area of the region enclosed by
y=4x
and
x=6-y^(2)
. Use horizontal strips to find the area. First find the
y
-coordinates of the two points where
y=4x
meets
x=6-y^(2)
. lower
y=c=(-1-19.62)/(8),
and upper
y=d=(-1+19.62)/(8)✓o
Hint:
g(y)
is the right curve - left curve. Then area of the region
=\int_c^d g(y)dy
where
g(y)=

0^(8)
Evaluate the definite integral to find Area
=

Question

Find the area of the region enclosed by

y=4x

and

x=6-y^(2)

. Use horizontal strips to find the area. First find the

y

-coordinates of the two points where

y=4x

meets

x=6-y^(2)

. lower

y=c=(-1-19.62)/(8),

and upper

y=d=(-1+19.62)/(8)✓o

Hint:

g(y)

is the right curve - left curve. Then area of the region

=\int_c^d g(y)dy

where

g(y)=

0^(8)

Evaluate the definite integral to find Area

=

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