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(Solved): Find the center, vertices, foci, and the equations of the asymptotes of the hyperbola. 9x^2 - 16y^2 ...


Find the center, vertices, foci, and the equations of the asymptotes of the hyperbola.

9x^2 - 16y^2 - 18x - 32y - 151= 0

\( 9 x^{2}-16 y^{2}-18 x-32 y-151=0 \)



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Solution:-Given that 9x2?16y2?18x?32y?151=0Find the standard form of the hyperbola.(x?1)216?(y+1)29=0This is the form of a hyperbola. Use this form to
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