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(Solved): Find the equation for the tangent plane to the surface z=e5x2+4y2 at the point (0,0,1). z=1z=1z= ...

$Find the equation for the tangent plane to the surface \( z=e^{5 x^{2}}+4 y^{2} \) at the point \( (0,0,1) \). \[ \begin{arra$

Find the equation for the tangent plane to the surface

z = e^{5 x^{2}} + 4 y^{2}

at the point

(0, 0, 1)

.

z = ? 1 z = 1 z = 0 z = 2

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