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Find the lengths of the sides of the triangle $ABC$ with the indicated vertices. $A(6,0,0)B(0,10,0)C(0,0,−16) $ Step 1 Let $A(6,0,0),B(0,10,0)$, and $C(0,0,−16)$ be the vertices of the triangle $ABC$ To find the length of each side of the triangle, use the distance formula for the length of the segment between two points $(x_{1},y_{1},z_{1})$ and $(x_{2},y_{2},z_{2})$. $d=(x_{2}−x_{1})_{2}+(y_{2}−y_{1})_{2}+(z_{2}−z_{1})_{2} $ Find the length of the side $AB$ by using the distance formula. $∣AB∣ =(0−6)_{2}+(10−0)_{2}+(−16 ×−(0))_{2}=(6)_{2}+(10)_{2}+( ××)_{2}1 $

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