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(Solved): Find the quadratic function f passing through the points (1,3) and (2,6). whose axis of symmetry ...




Find the quadratic function \( f \) passing through the points \( (1,3) \) and \( (-2,6) \). whose axis of symmetry is the li
Find the quadratic function passing through the points and . whose axis of symmetry is the line . Write in standard form.


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To find the quadratic function f passing through the points (1,3) and (?2,6) with an axis of symmetry at x=2, we can use the standard form of a quadratic function:   .
First, let's use the points (1,3) and (?2,6) to form two equations:
For point (1,3):    (equation 1)
For point (?2,6):   (equation 2)
Since the axis of symmetry is x=2, we know that the vertex of the parabola is at (2,k).

The x-coordinate of the vertex can be found using the formula   
In this case, x=2, so we have:

  equation 3)
Now, let's solve these equations to find the values of a, b, and c:
From equation 3, we can rearrange it to find b:
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