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(Solved): Find the solution of the initial value problem. y^('')+9y=\delta (t-\pi )-\delta (t-2\pi ),y(0)=0, ...
Find the solution of the initial value problem.
y^('')+9y=\delta (t-\pi )-\delta (t-2\pi ),y(0)=0,y^(')(0)=0Choose the correct answer.
y(t)=u_(\pi )sin(3(t-\pi ))-u_(2\pi )sin(3(t-2\pi ))
y(t)=(2)/(3)u_(\pi )cos(t-\pi )-(2)/(3)u_(2\pi )sin(t-2\pi )
y(t)=(1)/(3)u_(\pi )sin(3(t-\pi ))-(1)/(3)u_(2\pi )sin(3(t-2\pi ))
y(t)=(2)/(3)u_(\pi )sin(t-\pi )-(2)/(3)u_(2\pi )sin(t-2\pi )
y(t)=u_(\pi )sin(3t)-u_(2\pi )sin(3t)