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(Solved): Find the sum of the series n=0(1)nn!42n 1. sum =4 2. sum=e4 3. sum =e16 4. sum = ...

$Find the sum of the series \[ \sum_{n=0}^{\infty}(-1)^{n} \frac{4^{2 n}}{n !} \] 1. sum \( =4 \) 2. \( \operatorname{sum}=e^{$

Find the sum of the series

n = 0 ? ? (? 1)^{n} \frac{4 ^{2 n}}{n !}

1. sum

= 4

2.

sum = e^{? 4}

3. sum

= e^{16}

4. sum

= 16

5. sum

= e^{? 16}

6.

sum = e^{4}

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