(Solved): For the function shown below, draw tne secant line from x=0 to x=5. vraw: Use the graph to estimate ...

For the function shown below, draw tne secant line from $$x=0$$ to $$x=5$$. vraw: Use the graph to estimate the average rate of change from $$x=0$$ to $$x=5$$. (Round to three decimal places.) Average rate of change = Suppose that an object is moving along a vertical line. Its vertical position is given by the equation $$L(t)=?t^3?4t+9$$, where distance is measured in meters and time in seconds. Find the approximate value of the average velocity (accurate up to three or more decimal places) in the given time intervals. between $$t_1=3\mathrm{s}$$ and $$t_2=4\mathrm{s}:\frac{m}{8}$$ between $$t_1=2s$$ and $$t_2=8\mathrm{s}$$ : $$\frac{m}{8}$$ between $$t_1=4s$$ and $$t_2=85:\frac{m}{s}$$ Objective [1.5] The average rate of change between two points is equivalent to: The slope of the secant line at the first point The slope of the tangent line at the second point The slope of the tangent line at the first point The slope of the secant line between the points The slope of the tangent line between the points Question Help: $$?$$ Message instructor Section $$1.1$$ Homework Score: $$2/171/9$$ answered In the above graph of $$y=f(x)$$, find the slope of the secant line through the points $$(?2,f(?2))$$ and $$(2,ft$$ 2)). A falling object moves so that its height $$x$$ above the ground is given by the equation $$x=103+(?4.9)?t^2$$, where $$x$$ is in meters and $$t$$ is in seconds. Find the average velocity from $$t=1$$ to $$t=4$$, Answer: Units: Question Help: $$?$$ Message instructor What does the slope of a secant line represent? An instantaneous rate of change (at one point on the graph). An average rate of change (between two points on the graph).