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(Solved): \( \frac{4 \mathrm{~cm}}{\mathrm{U}=9 \mathrm{~m} / \mathrm{s}} \) A \( 4 \mathrm{~cm} \) diameter ...




\( \frac{4 \mathrm{~cm}}{\mathrm{U}=9 \mathrm{~m} / \mathrm{s}} \)
A \( 4 \mathrm{~cm} \) diameter pipe with a diameter of \( 8 \mathrm{~cm} \) in a hot water line with a black flow is provide
\( \frac{4 \mathrm{~cm}}{\mathrm{U}=9 \mathrm{~m} / \mathrm{s}} \) A \( 4 \mathrm{~cm} \) diameter pipe with a diameter of \( 8 \mathrm{~cm} \) in a hot water line with a black flow is provided it is being expanded. The transition zone is provided with an angle of inclination of 25 degrees.. Narrow section as a result of the expansion in diameter, if the pressure in its region is \( 80 \mathrm{kPa} \) and the flow rate is \( 9 \mathrm{~m} / \mathrm{s} \), then the resulting loss (in meters) and the pressure value in a wide cross section \( (\mathrm{kPa} \) 1) calculate


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