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(Solved): Give the general solution of
dydx=2xy22x+5y25.
ln(y21)=Ce2x2+10x
y1y+1=Ce2x2+10x
...
Give the general solution of
dydx=2xy2−2x+5y2−5.
ln(y2−1)=Ce2x2+10x
y−1y+1=Ce2x2+10x
y+1y−1=Ce2x2+5x
y−1y+1=Ce2x2+5x
y+1y−1=Ce2x2+10x
None of the above.