Given: C2H2 (g) + 52O2 (g) -- 2CO2 (g) + H2O (l) Delta H deg = 1299.5 kJ C (s) + O2 (g) -- CO2 (g) Delta H deg = 393.5 kJ H2 (g) + 12O2 (g) -- H2O (l) Delta H deg = 285.8 kJ What is the Delta H deg for this reaction? 3 C (s) + 3/2 H2 (g) --- 3/2 C2H2 (g)

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Given:  C2H2 (g) + 52O2 (g) --> 2CO2 (g) + H2O (l)   Delta H deg  = 1299.5 kJ  C (s) + O2 (g) --> CO2 (g)   Delta H deg  = 393.5 kJ  H2 (g) + 12O2 (g) --> H2O (l)   Delta H deg  = 285.8 kJ     What is the  Delta H deg  for this reaction?  3 C (s) + 3/2  H2 (g) ---> 3/2 C2H2 (g)

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Expert Answer to -  Given:  C2H2 (g) + 52O2 (g) --> 2CO2 (g) + H2O (l)   Delta H deg  = 1299.5 kJ  C (s) + O2

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Solution for -  Given:  C2H2 (g) + 52O2 (g) --> 2CO2 (g) + H2O (l)   Delta H deg  = 1299.5 kJ  C (s) + O2

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This an additional answer to -  Given:  C2H2 (g) + 52O2 (g) --> 2CO2 (g) + H2O (l)   Delta H deg  = 1299.5 kJ  C (s) + O2

(Solved): Given: C2H2 (g) + 52O2 (g) --> 2CO2 (g) + H2O (l) \Delta H\deg = 1299.5 kJ C (s) + O2 ...

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