Given H_(0): theta =kH_(1): theta =2x(1)/(2) alpha beta alpha ( beta )/(64)=1f(x)=(1 theta )x^( theta ), theta 0,0. You are testing the hypothesis H_(0): theta =k against the H_(1): theta =2, and you use x(1)/(2) as a critical region in this one sided test. If the Type I error is alpha and Type II error is beta such that alpha

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Given H_(0): theta =kH_(1): theta =2x>(1)/(2) alpha  beta  alpha  ( beta )/(64)=1f(x)=(1  theta )x^( theta ), theta >0,0. You are testing the hypothesis H_(0): theta =k against the H_(1): theta =2, and you use x>(1)/(2) as a critical region in this one sided test. If the Type I error is  alpha  and Type II error is  beta  such that  alpha  ( beta )/(64)=1 what is k ?

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(Solved): Given H_(0):\theta =kH_(1):\theta =2x>(1)/(2)\alpha \beta \alpha (\beta )/(64)=1f(x)=(1 \theta ) ...

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