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(Solved): Hand calculations only Show steps of your solution. Handwrite your solution The following table is o ...
Hand calculations only Show steps of your solution. Handwrite your solution The following table is obtained from the function
f=1-x+x^(3)\table[[x,0.0,0.1,0.2,0.3,0.4,0.5,0.6,0.7,0.8],[f,1.0,0.9010,0.8080,0.7270,0.6640,0.6250,0.6160,0.6430,0.7120]] (20%) a. Find
f(0.38), using Linear Interpolating polynomial. Find the actual error and estimated minimum and maximum errors. (22%) b. Find
f(0.38)using
3^(rd )degree Newton Polynomial. Set up divided difference table using relevant points. (22%) c. Find
f^(')(0.4), Use central difference and Richardson's extrapolation to find answer with an error
\epsi =O(0.1^(6)). (Do not find the error) (20%) d. Find
\int_(0.0)^(0.8) f(x)dx; Use Trapezoidal rule(Composite Trapezoidal rule). Find the actual, minimum and maximum errors. (16%) e. Find
\int_(0.0)^(0.8) f(x)dx. Use Simpson's
(1)/(3)rule.
