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(Solved): help!!!!! The length of a rectangle is 5 yd less than double the width, and the area of the rectangl ...



help!!!!!

The length of a rectangle is 5 yd less than double the width, and the area of the rectangle is \( 33 \mathrm{yd}^{2} \). Find
The length of a rectangle is 5 yd less than double the width, and the area of the rectangle is \( 33 \mathrm{yd}^{2} \). Find the dimensions of the rectangle. \begin{tabular}{l} Length: \\ weth: Dyd \\ \hline \end{tabular}


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