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(Solved): i cant figure out how to do this math lab code  \[ E=\frac{h c}{\lambda} / J 2 \mathrm{eV} \] W ...



i cant figure out how to do this math lab code 

\[
E=\frac{h c}{\lambda} / J 2 \mathrm{eV}
\]
Where:
\[
h=15.847 \quad c=43.633 \quad J 2 \mathrm{eV}=0.955
\]
and
\[
\lambda
\[ E=\frac{h c}{\lambda} / J 2 \mathrm{eV} \] Where: \[ h=15.847 \quad c=43.633 \quad J 2 \mathrm{eV}=0.955 \] and \[ \lambda=400 \text { to } 472 \text { in steps of } 8 \text { (meaning } 400,408,416 \ldots \text { ) } \] Print both the value of lambda and the corresponding Photon energy ONLY where the Photon Energy is greater than \( 1.631 \) and less than \( 1.661 \) After ustaying the value of Photon Energy, display the value for \( E \) a line showing the units as:


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The required program in MATLAB is given below: h = 15.842; c = 43.633; J2eV = 0.955 lambda = [400:8:472] for lambda = [360:8:472] E = ((h*c)/lambda)/J
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