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(Solved): I need assistance with Part C;   The demand for a new computer game can be modeled by \( p( ...



I need assistance with Part C;

 

The demand for a new computer game can be modeled by \( p(x)=55-3 \ln x \), for \( 0 \leq x \leq 800 \), where \( p(x) \) is

The demand for a new computer game can be modeled by \( p(x)=55-3 \ln x \), for \( 0 \leq x \leq 800 \), where \( p(x) \) is the price consumers will pay, in dollars, and \( x \) is the number of games sold, in thousands. Recall that total revenue is given by \( R(x)=x \cdot p(x) \). Complete parts (a) through (c) below. a) Find \( R(x) \) \[ R(x)=x(55-3 \ln x) \] b) Find the marginal revenue, \( \mathrm{R}^{\prime}(\mathrm{x}) \). \[ R^{\prime}(x)=52-3 \ln (x) \] c) How many units will be sold if the price that consumers are willing to pay is \( \$ 50 ? \) The number of units that will be sold is (Round to the nearest whole number as needed.)


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Given, p(x)=55?3ln?x, 0?x?800 (a)Revenu
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