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(Solved): If \( \mathrm{Vab}=30 \mathrm{~V} \), find the voltage drop across \( \mathrm{C} 2 \) as shown. a) ...




If \( \mathrm{Vab}=30 \mathrm{~V} \), find the voltage drop across \( \mathrm{C} 2 \) as shown.
a) \( \mathrm{V} 2=30 \mathrm
If \( \mathrm{Vab}=30 \mathrm{~V} \), find the charge on \( \mathrm{C} 1 \) as shown
a) \( Q 1=0.09 \) C b) \( Q 1=90( \) c)
If \( \mathrm{Vab}=30 \mathrm{~V} \), find the voltage drop across \( \mathrm{C} 2 \) as shown. a) \( \mathrm{V} 2=30 \mathrm{~V} \) b) \( \mathrm{V} 2=15 \mathrm{~V} \) c) \( \mathrm{V} 2=5 \mathrm{~V} \) d) \( \mathrm{V} 2=20 \mathrm{~V} \) b c d \( a \) If \( \mathrm{Vab}=30 \mathrm{~V} \), find the charge on \( \mathrm{C} 1 \) as shown a) \( Q 1=0.09 \) C b) \( Q 1=90( \) c) \( Q 1=0.18 \mathrm{C} \) d) \( Q 1=180 \mathrm{C} \)


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1) the rightmost branch has three 9 mF capacitors in series. Their combined capacitance is 1C=19+19+19 C=3 mF In the left branch, we have
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