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(Solved): In Question2.java, complete the method evenVsOdd(int[] numbers) such that, given an array of integer ...



In Question2.java, complete the method evenVsOdd(int[] numbers) such that, given an array of integers (numbers), the method will compare how many even and odd values exist in the array. If there are more even values than odd, the method will return the String: "EVEN wins!", if there are more odd than even values, the method will return "ODD wins!", however, in any other situation, including when the numbers array has no values, the method will return: "no winners :("



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