(Solved): In this problem, we will consider the following situation as depicted in the diagram: (Figure 1) A b ...

In this problem, we will consider the following situation as depicted in the diagram: (Figure 1) A block of mass m slides at a speed v along a horizontal smooth table. It next slides down a smooth ramp, descending a height hℎ, and then slides along a horizontal rough floor, stopping eventually. Assume that the block slides slowly enough so that it does not lose contact with the supporting surfaces (table, ramp, or floor).

You will analyze the motion of the block at different moments using the law of conservation of energy.

-Part D: Using conservation of energy, find the speed vb of the block at the bottom of the ramp.

Express your answer in terms of some or all the variables m, v, and ℎ and any appropriate constants.

$K=\frac{1}{2}m{v}^2$ Potential energy, in contrast, has many forms. Two forms that you will be dealing with often are gravitational and elastic potential energy. Gravitational potential energy is the energy possessed by elevated objec For small heights, it can be found as $U_{\mathrm{g}}=mgh$ where $m$ is the mass of the object, $g$ is the acceleration due to gravity, an $h$ is the elevation of the object above the zero level. The zero level is the elevation at which the gravitational potential energy is assumed to be zero Figure 1 of 1