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(Solved): Indicate the concentration of each ion present in the solution formed by mixing \( 10.0 \mathrm{~mL ...
Indicate the concentration of each ion present in the solution formed by mixing \( 10.0 \mathrm{~mL} \) of \( 0.130 \mathrm{M} \mathrm{HCl} \) and 120 mL of \( 0.600 \mathrm{M} \mathrm{HCl} \). (Write your answer as \( a, b, c \), or d.) a) \( 0.730 \mathrm{M} \mathrm{H}^{+} \)and \( 0.730 \mathrm{M} \mathrm{Cl}^{-} \) b) \( 0.386 \mathrm{M} \mathrm{H}^{+} \)and \( 0.386 \mathrm{M} \mathrm{Cl}^{-} \) c) \( 0.331 \mathrm{MH}^{+} \)and \( 0.662 \mathrm{M} \mathrm{Cl}^{-} \) d) \( 0.730 \mathrm{M} \mathrm{H}^{+} \)and \( 0.331 \mathrm{M} \mathrm{Cl}^{-} \) Answ
Given: The volume of 0.130 M HCl = 10.0 mL = 10.0 x 10-3 L = 0.01 L The molarity of first HCl solution = 0.130 M The volume of 0.600 M HCl = 12.0 mL = 12.0 x 10-3 L = 0.012 L The molarity of second HCl solution = 0.600 M Find: Find the concentration