(Solved): It takes 17.5mL of a 0.250M solution of NaOH to neutralize 20.0mL of a HCl solution of an unkno ...

It takes $17.5\mathrm{mL}$ of a $0.250\mathrm{M}$ solution of $\mathrm{NaOH}$ to neutralize $20.0\mathrm{mL}$ of a $\mathrm{HCl}$ solution of an unknown concentration. What was the molar concentration of the $\mathrm{HCl}$ solution? Hint: 1 mole of a monoprotic acid neutralizes 1 mole of base $\left({\mathrm{OH}}^{-}\right)$. Question 9 If you had $440.0\mathrm{mL}$ of $0.475\mathrm{M}$ of $\mathrm{HCl}$, how many grams of $\mathrm{Mg}(\mathrm{OH}{)}_2$ would be required to neutralize it?