Just the matlab code please, thank you! A simply supported beam is loaded as shown below. Using singularity functions, the moment ( (M(x)) ) along the beam can be expressed by the equation [ M(x)=-10 left[^{2}-^{2} right]+15^{1}+150^{0}+57 x ] where ( x ) is the distance from the left side of the beam in meters. By definition, the singularit

Question

Just the matlab code please, thank you!  A simply supported beam is loaded as shown below. Using singularity functions, the moment  ( (M(x))  ) along the beam can be expressed by the equation  [ M(x)=-10 left[^{2}-^{2} right]+15^{1}+150^{0}+57 x  ] where  ( x  ) is the distance from the left side of the beam in meters. By definition, the singularity function can be expressed as follows:  [ ^{n}= left { begin{aligned} (x-a)^{n}, & x>a    0, & x  leq a  end{aligned} right.  ] By hand, use 2 iterations of the bisection method to find the point where the moment equals 0 . Let the lower bound be 1 meter and the upper bound be 6 meters. Use Matlab's fzero function to find the point between  ( x=1  ) meter and  ( x=6  ) meters where the moment equals 0. Submit your Matlab

Accepted Answer

Expert Answer to - Just the matlab code please, thank you!  A simply supported beam is loaded as shown below. Using sin

Answer

Solution for - Just the matlab code please, thank you!  A simply supported beam is loaded as shown below. Using sin

Answer

This an additional answer to - Just the matlab code please, thank you!  A simply supported beam is loaded as shown below. Using sin

(Solved): Just the matlab code please, thank you! A simply supported beam is loaded as shown below. Using sin ...

View Expert Answer

Expert Answer

Buy This Answer $5

Place Order

We Provide Services Across The Globe