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(Solved): K(HAc)=1.8105, calculate the pH of following solutions: (1) 0.20molL1HAc solutions ...



\( \mathrm{K}^{\ominus}(\mathrm{HAc})=1.8 \times 10^{-5} \), calculate the \( \mathrm{pH} \) of following solutions:
(1) \( 0

, calculate the of following solutions: (1) solutions. (2) is mixed with (same volume).


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The concentration given of acetic acid is   .
The given dissociation constant of acetic acid is   .
We know that the dissociation reaction of acetic acid is as follows:
  
So, according to the data, let   be the concentration of hydrogen ions. So,



Now, we know the relation between the dissociation constant and concentration of hydrogen ion we get,
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