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LaTech Stewart8e Ch13Sec4: Problem 5 (1 point) Given that the acceleration vector is

`a(t)=(-9cos(-3t))i+(-9sin(-3t))j+(-5t)k`

, the initial velocity is

`v(0)=i+k`

, and the initial position vector is

`r(0)=i+j+k`

, compute: A. The velocity vector

`v(t)=i+j+k`

B. The position vector

`r(t)=i+,j+dotsk`

Note: the coefficients in your answers must be entered in the form of expressions in the variable

`t;`

e.g. "

`5cos(2t)`

"