LaTech Stewart8e Ch13Sec4: Problem 5 (1 point) Given that the acceleration vector is
a(t)=(-9cos(-3t))i+(-9sin(-3t))j+(-5t)k
, the initial velocity is
v(0)=i+k
, and the initial position vector is
r(0)=i+j+k
, compute: A. The velocity vector
v(t)=i+j+k
B. The position vector
r(t)=i+,j+dotsk
Note: the coefficients in your answers must be entered in the form of expressions in the variable
t;
e.g. "
5cos(2t)
"