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(Solved): LaTech Stewart8e Ch13Sec4: Problem 5 (1 point) Given that the acceleration vector is a(t)=(-9cos(-3t ...



LaTech Stewart8e Ch13Sec4: Problem 5 (1 point) Given that the acceleration vector is

a(t)=(-9cos(-3t))i+(-9sin(-3t))j+(-5t)k

, the initial velocity is

v(0)=i+k

, and the initial position vector is

r(0)=i+j+k

, compute: A. The velocity vector

v(t)=i+j+k

B. The position vector

r(t)=i+,j+dotsk

Note: the coefficients in your answers must be entered in the form of expressions in the variable

t;

e.g. "

5cos(2t)

"



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