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Let

`A=[[1,-3,-2],[-2,2,0],[4,0,4]]`

and

`b=[[b_(1)],[b_(2)],[b_(3)]]`

. Show that the equation

`Ax=b`

does not have a solution for all possible

`b_(2)`

and describe the set of all

`b`

for which Ax

`=b`

does have

`a`

solution. How can it be shown thas the equation

`Ax=b`

does not have a solutise for all possoble

`b`

? Chosse the coerect answer belowc A. Row reduce the matrix Ato demonstrate that A does not have a pivot position in every row. B. Row reduce the matric A to demonstrate that A has a pivot position in every row. C. Find a vector

`x`

for which

`Ax=b`

is the zero wector. D. Row reduce the augmented matrix

`AB`

to demonstrate that

`AB`

has a pivot position in every sow E. Find a vector

`b`

for which the solution to

`Ax=b`

is the zero vector. Describe the set of all

`b`

for which

`Ax=b`

does have a solution

`0=`

(Type an expcession using

`b_(1),b_(2)`

, and

`b_(y)`

as the variables and 1 as the coeficient of by.)