Let
A=[[1,-3,-2],[-2,2,0],[4,0,4]]
and
b=[[b_(1)],[b_(2)],[b_(3)]]
. Show that the equation
Ax=b
does not have a solution for all possible
b_(2)
and describe the set of all
b
for which Ax
=b
does have
a
solution. How can it be shown thas the equation
Ax=b
does not have a solutise for all possoble
b
? Chosse the coerect answer belowc A. Row reduce the matrix Ato demonstrate that A does not have a pivot position in every row. B. Row reduce the matric A to demonstrate that A has a pivot position in every row. C. Find a vector
x
for which
Ax=b
is the zero wector. D. Row reduce the augmented matrix
AB
to demonstrate that
AB
has a pivot position in every sow E. Find a vector
b
for which the solution to
Ax=b
is the zero vector. Describe the set of all
b
for which
Ax=b
does have a solution
0=
(Type an expcession using
b_(1),b_(2)
, and
b_(y)
as the variables and 1 as the coeficient of by.)