(Solved): Let a_(n)=(6n)/(8n 1). (a) Determine whether {a_(n)} is convergent or divergent. If it is convergent ...

Let

. (a) Determine whether

is convergent or divergent. If it is convergent, find the limit. (If the quantity diverges, enter DIVERGES.)

(b) Determine whether

is convergent. Converges; the limit of the terms

is a constant as

goes to

. Converges; the series is a constant multiple of a geometric series Diverges; the series is a constant multiple of the harmonic series. Diverges; the limit of the terms

is not 0 as

goes to

. Diverges; the sequence

diverges as

goes to

.