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(Solved): Let f(x)=6x+1-9e^(x). Then the equation of the tangent line to the graph of f(x) at the point (0,-8) ...



Let

f(x)=6x+1-9e^(x)

. Then the equation of the tangent line to the graph of

f(x)

at the point

(0,-8)

is given by

y=mx+b

for

m=

b=
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