Members in Unbraced Frames The correct answer is "satisfactory, the result for the interaction equation =0.748" 6.7-1 A W14
\times 82
of 50 ksi steel is to be investigated for use as a beam-column in an unbraced frame. The length is 14 feet. First-order analyses of the frame were performed for both the sway and the nonsway cases. The factored loads and moments corresponding to one of the load combinations to be investigated are given for this member in the following table: \table[[Type of analysis,
P_(z)
(kips),
M_(hpp)
(ft-kips),
M_(bst)
(ft-kips)],[Nonsway,400,45,24],[Sway,-,40,95]] Bending is about the strong axis, and all moments cause double-curvature bending (all end moments are in the same direction, that is, all clockwise or all counterclockwise). The following values are also available from the results of a preliminary design:
P_(craty )=40,000kips,P_(shoy )=6,000kips
Use
K_(x)=1.0
(nonsway case),
K_(x)=1.7
(sway case), and
K_(y)=1.0
. Use LRFD and determine whether this member satisfies the provisions of the AISC Specification for the given load combination. Please show all your work and explain all steps. It's for understanding purposes. The answer should be "satisfactiry, result of interaction equation =0.748" explain how to get this result in detail please The answer should be 0.748 please explain thoroughly how we get this result Members in Unbraced Frames 6.7-1 A W14
\times 82
of 50 ksi steel is to be investigated for use as a beam-column in an unbraced frame. The length is 14 feet. First-order analyses of the frame were performed for both the sway and the nonsway cases. The factored loads and moments corresponding to one of the load combinations to be investigated are given for this member in the following table: \table[[Type of analysis,
P_(u)(kips)
,
M_(top)(ft-kips)
,
M_(bot )(ft-kips)