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(Solved):   1. \( (2 p) \) Convert \( (153)_{10} \) to base 8 . 2. (2p) Convert \( (153)_{8} \) to bas ...



1. \( (2 p) \) Convert \( (153)_{10} \) to base 8 .
2. (2p) Convert \( (153)_{8} \) to base 10 .
3. (1p) Convert \( (1010111)

 

1. \( (2 p) \) Convert \( (153)_{10} \) to base 8 . 2. (2p) Convert \( (153)_{8} \) to base 10 . 3. (1p) Convert \( (1010111)_{2} \) to base 8 . 4. (4p) Use 2's complement to subtract binary 3 from binary 8.


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(153)10=1×102+5×101+3×1001538=8×(19)+1=8×(8×2+3)+1×80=2×82+3×81+1×80 (153)10 = (231)8 (base 8)
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