a salvage value of ( $ 7,000 ) after 4 years. At a MARR of ( 12 % ) per year, when comparing the alternatives, the equation of PW is written as: a. ( P W X=-20,000-9000( mathrm{P} / mathrm{A}, 12 %, 4)+5000 left( mathrm{P} / mathrm{F}_{1}, 12 %, 4 right)-15000( mathrm{P} / mathrm{F}, 12 %, 4) ) b. ( P W X=-20,000-9000(P / A

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a salvage value of  (  $ 7,000  ) after 4 years. At a MARR of  ( 12  %  ) per year, when comparing the alternatives, the equation of PW is written as: a.  ( P W X=-20,000-9000( mathrm{P} /  mathrm{A}, 12  %, 4)+5000 left( mathrm{P} /  mathrm{F}_{1}, 12  %, 4 right)-15000( mathrm{P} /  mathrm{F}, 12  %, 4)  ) b.  ( P W X=-20,000-9000(P / A, 12  %, 4)+5000(P / F, 12  %, 2)-15000(P / F, 12  %, 2)  ) c. None of these answers d.  ( P W X=-20,000+9000(P / A, 12  %, 4)+5000(P / F, 12  %, 4)-15000(P / F, 12  %, 2)  )

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(Solved): a salvage value of \( \$ 7,000 \) after 4 years. At a MARR of \( 12 \% \) per year, when c ...

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