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(Solved):   Find the area of the surface generated by revolving the given curve about the \( x \)-axis ...


Find the area of the surface generated by revolving the given curve about the \( x \)-axis. \[ y=\sqrt{4-x^{2}} \quad-1 \leq

 

Find the area of the surface generated by revolving the given curve about the \( x \)-axis. \[ y=\sqrt{4-x^{2}} \quad-1 \leq x \leq 1 \]


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Put the value of y and ds in
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