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I know you have to use the equation E=mC^2. I solved the problem and got an answer of ...
I know you have to use the equation E=mC^2. I solved the problem and got an answer of 1.77 × 10^10. Please show all the calculations associated with this. Thank you in advance.
Check Your Learning What is the binding energy for the nuclide \( { }_{9}^{19} \mathrm{~F} \) (atomic mass: \( 18.9984 \mathrm{amu} \) ) in \( \mathrm{MeV} \) per nucleus? ANSWER: 148.4 MeV