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(Solved):   I know you have to use the equation E=mC^2.  I solved the problem and got an answer of ...



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What is the binding energy for the nuclide \( { }_{9}^{19} \mathrm{~F} \) (atomic mass: \( 18.9984 \mathr

 

I know you have to use the equation E=mC^2.  I solved the problem and got an answer of 1.77 × 10^10.  Please show all the  calculations associated with this.  Thank you in advance.

Check Your Learning What is the binding energy for the nuclide \( { }_{9}^{19} \mathrm{~F} \) (atomic mass: \( 18.9984 \mathrm{amu} \) ) in \( \mathrm{MeV} \) per nucleus? ANSWER: 148.4 MeV


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answer) binding energy per nucleus given by the equation ; delta m * 931.5 MeV where , delt
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