(Solved):   I need this answered very urgently and with as much steps as possible, thanks. Let coordin ...

 

I need this answered very urgently and with as much steps as possible, thanks.

Let coordinates of foci of the ellipse \( A x^{2}+B y^{2}+C x+D y+F=0 \) are \( F_{1}\left(a_{1}, b_{1}\right) \) and \( F_{2}\left(a_{2}, b_{2}\right) \), and \( \varepsilon \)-its eccentricity. Then \( \mathrm{A}=4, \mathrm{~B}=2, \mathrm{C}=1, \mathrm{D}=1, \mathrm{~F}=-4 \quad a_{1} / a_{2}+b_{1} / b_{2}+\varepsilon \) equals to