(Solved):   PIP 0255 INTRODUCTION TO PHYSICS Figure 4.3 (a): Rocket Launch? Maximum Altitude Altit ...

 

PIP 0255 INTRODUCTION TO PHYSICS Figure 4.3 (a): Rocket Launch? Maximum Altitude ? Altitude = 1200 m Fuel runs out a = g (downwards) Figure 4.3 (b): Rocket Drop! Maximum Altitude 10 a = + 3.2 m/s² a = g (downwards) 21 MAY 2022 ? (c) Refer to Figure 4.3 (a): During the launching of a rocket, a rocket rises vertically, from rest, with an acceleration of 3.2 m/s² until it runs out of fuel at an "altitude" (fancier, technical term for height) of 1200 m. After this point (1200 m), the rocket's acceleration is that of gravity (downwards). Even so, the rocket will still reach a maximum altitude. Refer to Figure 4.3 (b): Once the rocket has reached maximum altitude, it will then drop back down to earth, till it hits the ground (where the altitude is considered zero). Take g = 9.8 m/s². Based on this, answer the following (Show your calculation): (i) Determine the velocity (v) of the rocket at the altitude of 1200 m. (2 x ½ mark) (ii) Find the time (t) it takes the rocket to reach this altitude of 1200 m. (2 x 1 mark) (iii) Find the maximum altitude that the rocket can reach even when its fuel has run out (Note: at that point when the fuel is used up, acceleration, a, is no longer 3.2 m/s²). (2 x ½ mark) (iv) Find the velocity that the rocket will hit the ground on earth (on impact, altitude = 0) when it drops back down to earth from the maximum altitude. (2 × ½ mark)