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(Solved): OI've been looking at other examples of this problem with different numbers but I am not understandi ...



An express train passes through a station. It enters with an initial velocity of \( 22.8 \mathrm{~m} / \mathrm{s} \) and deceOI've been looking at other examples of this problem with different numbers but I am not understanding the equations that are being set up. 

An express train passes through a station. It enters with an initial velocity of \( 22.8 \mathrm{~m} / \mathrm{s} \) and decelerates at a rate of \( 0.160 \mathrm{~m} / \mathrm{s}^{2} \) as it goes through. The station is \( 201 \mathrm{~m} \) long. (a) How long (in s) is the nose of the train in the station? \( \mathrm{s} \) (b) How fast (in m/s) is it going when the nose leaves the station? \[ \mathrm{m} / \mathrm{s} \] (c) If the train is \( 130 \mathrm{~m} \) long, when (in s) does the end of the train leave the station? 5 (d) What is the velocity (in \( \mathrm{m} / \mathrm{s} \) ) of the end of the train as it leaves? (Enter the magnitude.) \[ \mathrm{m} / \mathrm{s} \]


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initial velocity u=22.6m/s deceleration a=-0.16m/s^2 length of station d=201 m time taken to travel d=201m with this initial speed and deceleration. d
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