(Solved): Open the valve to add water to the soda pop solution until it reachs a final volume of 1.00L. ...

Open the valve to add water to the soda pop solution until it reachs a final volume of $1.00\mathrm{L}$. How does this affect the concentrations of ${\mathrm{H}}_3{\mathrm{O}}^{+}$and ${\mathrm{OH}}^{-}$? The concentration of ${\mathrm{H}}_3{\mathrm{O}}^{+}$will increase and the concentration of ${\mathrm{OH}}^{-}$will decrease. The concentration of ${\mathrm{H}}_3{\mathrm{O}}^{+}$will decrease and the concentration of ${\mathrm{OH}}^{-}$will increase. The concentration of both ${\mathrm{H}}_3{\mathrm{O}}^{+}$and ${\mathrm{OH}}^{-}$will increase. The concentrations of ${\mathrm{H}}_3{\mathrm{O}}^{+}$and ${\mathrm{OH}}^{-}$will remain the same. The concentration of both ${\mathrm{H}}_3{\mathrm{O}}^{+}$and ${\mathrm{OH}}^{-}$will decrease. Open the valve to add water to the drain cleaner solution until it reachs a final volume of $1.00\mathrm{L}$. How does this affect the concentrations of ${\mathrm{H}}_3{\mathrm{O}}^{+}$and ${\mathrm{OH}}^{-}$? The concentration of ${\mathrm{H}}_3{\mathrm{O}}^{+}$will increase and the concentration of ${\mathrm{OH}}^{-}$will decrease. The concentration of both ${\mathrm{H}}_3{\mathrm{O}}^{+}$and ${\mathrm{OH}}^{-}$will decrease. The concentration of ${\mathrm{H}}_3{\mathrm{O}}^{+}$will decrease and the concentration of ${\mathrm{OH}}^{-}$will increase. The concentrations of ${\mathrm{H}}_3{\mathrm{O}}^{+}$and ${\mathrm{OH}}^{-}$will remain the same. The concentration of both ${\mathrm{H}}_3{\mathrm{O}}^{+}$and ${\mathrm{OH}}^{-}$will increase.