Part A IP A vertical spring stores 0.930 J in spring potential energy when a
3.5-kg
mass is suspended from it. By what multiplicative factor does the spring potential energy change if the mass attached to the spring is doubled?
(U_(2))/(U_(1))=(1)/(2)
(U_(2))/(U_(1))=(1)/(\sqrt(2))
(U_(2))/(U_(1))=\sqrt(2)
(U_(2)^(**))/(U_(1))=2
(U_(i))/(U_(1))=4
(U_(2))/(U_(1))=8