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(Solved): Part A: Make a piecewise function h(x) (format in the picture) that is not differentiable but is con ...



Part A: Make a piecewise function h(x) (format in the picture) that is not differentiable but is continuous at x = a. Let f(x) = 1/(x^3 + 2x). Create a g(x) different from f(x) and select the 'a' value. Type both your functions into a graphing software (https://www.desmos.com/calculator) and insert them below. Provide an explanation to explain why part A's piecewise function is not is not differentiable at x = a despite the function being continuous at x = a ('a' is chosen value).
Part B: Repeat part A with the same f(x) = 1/(x^3 + 2x) and the same chosen 'a' value, and choose a new or keep the same g(x) function, and create a piecewise function h(x) that IS differentiable at x = a. Then insert the graph piecewise function, and provide an algebraic solution to prove the piecewise function is differentiable at x = a. First prove continuity and then differentiability. Use proper limit notation.\( h(x)=\left\{\begin{array}{c}f(x) x<a \\ g(x) x>=a\end{array}\right. \)



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Let g(x)=12x+1And let a=1Then h(x) is continuous at
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