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(Solved): please answer all of them asap Determine the interval(s) over which \( f(x)=(x+3)^{3} \) is concave ...
please answer all of them asap
Determine the interval(s) over which \( f(x)=(x+3)^{3} \) is concave upward. A. \( (-\infty, \infty) \) B. \( (-\infty,-3) \) C. \( (-3, \infty) \) D. \( (-\infty, 3) \)
Find \( f_{y}(-2,-3) \) for the function \( f(x, y)=7 y^{2}+5 x^{3}-4 x^{5} y \) A. 170 B. 86 C. \( -170 \) D. \( -86 \)
(x) for \( f(x)=5 x^{4}-6 x^{2}+7 \) \[ \begin{array}{l} f^{\prime \prime}(x)=20 x^{2}-12 \\ f^{\prime \prime}(x)=60 x^{2}-12 \\ f^{\prime \prime}(x)=60 x^{2}-12 x \\ f^{\prime \prime}(x)=20 x^{2}-12 x \end{array} \]
\( f(7,3) \) when \( f(x, y)=7 x+3 y-6 \) A. 52 B. 49 C. 58 D. 45