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(Solved): Please answer asap In the figure, a solid 0.2kg ball rolls smoothly from rest (starting at height ...



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Please answer asap

In the figure, a solid ball rolls smoothly from rest (starting at height ) until it leaves the horizontal section at the end of the track, at height . How far horizontally from point does the ball hit the floor?


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Here apply law of conservation of mechanical energy and then: mgH=(1/2)mv2+(1/2)I?2+mgh (1) .As I = (2/5)mr2 and ?=v/r .Substitute this in equation (1) .Therefore mgH=(1/2)mv2+(1/2)(2/5)mr2 *(v2/r2)+mgh (2).

Given ,
m=0.2 kg
H=6m
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