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(Solved): Please answer asap In the figure, a solid 0.2kg ball rolls smoothly from rest (starting at height ...
Please answer asap
In the figure, a solid 0.2kg ball rolls smoothly from rest (starting at height H=6.0m ) until it leaves the horizontal section at the end of the track, at height h=2.3m. How far horizontally from point A does the ball hit the floor?
Here apply law of conservation of mechanical energy and then: mgH=(1/2)mv2+(1/2)I?2+mgh (1) .As I = (2/5)mr2 and ?=v/r .Substitute this in equation (1) .Therefore mgH=(1/2)mv2+(1/2)(2/5)mr2 *(v2/r2)+mgh (2).Given ,m=0.2 kg H=6m