(Solved): please help (10 points) As an illustration of the difficulties that may arise in using the method ...

please help

(10 points) As an illustration of the difficulties that may arise in using the method of undetermined coefficients, consider 5-6: 1]+2) a. Form the complementary solution to the homogeneous equation. -1 e^(2) yc(t) = 1 + C2 1 e (2) ai is a constant vector, does not work. In fact, if yp had this b. Show that seeking a particular solution of the form yp(t) = e2a, where a = form, we would arrive at the following contradiction: a a2 = aj and a2 = dj- c. Show that seeking a particular solution of the form y(t) = teta, where a = this form, we would arrive at the following contradiction: = (a) is a constant vector, does not work either. In fact, if yp had az = a and a = and a2 =