(Solved): please help I need this in asap It takes a golfer a total of three strokes to put the ball in the h ...

please help I need this in asap

It takes a golfer a total of three strokes to put the ball in the hole. The displacements of the three strokes are as follows: \( d_{1}=4.00 \mathrm{~m} \) the north, \( d_{2}=1.90 \mathrm{~m} \) northeast, and \( d_{3}=0.90 \mathrm{~m} \) at \( \theta=25.0^{\circ} \) west of south, as shown in the figure. If the golfer had made the hole in a single shot, what would be the displacement of the ball? (Assume the positive \( y \) - and \( x \)-axes are in the north and east directions, respectively. Give the magnitude of your answer in meters and the direction in degrees north of east.) i) magnitude Let \( +x \) be east, and \( +y \) be north. Write each of the displacements in unit-vector notation. Note that "northeast" means \( 45^{\circ} \) north of east. Use the figure to help you determine the signs of the components, and sum the displacement vectors to find the total displacement. Then use the Pythagorean theorem to find the magnitude. \( m \) direction \( { }^{\circ} \) north of east