PLEASE HELP ITS MY 3RD TIME POSTING THIS!!!!! pleaseeee
$y=4-x$
$\begin{array}{l}y=\frac{1}{\sqrt{2 \pi}} e^{-x^{-1 / 3}} \\ y=0 \\ x=0 \\ x=1\end{array}$
$Find the arc length of the graph of the function over the indicated interval. \[ y=\frac{2}{3}\left(x^{2}+1\right)^{3 / 2} \]$
$Set up and evaluate the definite integral for the area of the surface generated by revolving the curve about the x-axis. \{Ro$

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PLEASE HELP ITS MY 3RD TIME POSTING THIS!!!!! pleaseeee
$y=4-x$

$\begin{array}{l}y=\frac{1}{\sqrt{2 \pi}} e^{-x^{-1 / 3}} \\ y=0 \\ x=0 \\ x=1\end{array}$

$Find the arc length of the graph of the function over the indicated interval. \[ y=\frac{2}{3}\left(x^{2}+1\right)^{3 / 2} \]$

$Set up and evaluate the definite integral for the area of the surface generated by revolving the curve about the x-axis. \{Ro$

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(Solved): PLEASE HELP ITS MY 3RD TIME POSTING THIS!!!!! pleaseeee y=4x y=21ex1/3y=0x=0x=1 ...