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(Solved): Please help. thanks :) A stone is thrown vertically upward from a platform that is 33 feet above gro ...



Please help. thanks :)
A stone is thrown vertically upward from a platform that is 33 feet above ground at a rate of 65 feet per second. Use the pro
A stone is thrown vertically upward from a platform that is 33 feet above ground at a rate of 65 feet per second. Use the projectile formula \( h=-16 t^{2}+v_{0} t+h_{0} \) to find how long it will take the stone to reach its maximum height, and then find the maximum height the stone reaches. [Recall that \( v_{0} \) is the initial velocity of the object and \( h_{0} \) is the inital height of the object.] Answer: The stone reaches its maximum height after The maximum height the stone reaches is Note: Round any numerical responses to two decimal places. If there are multiple answers, separate them with commas.


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Given that: h=?16t2+v0t+h0 put v0=65
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