(Solved): Q 5. Minimum water elevation on upstream side of a diversion weir's Spillway is 400m. a) The mini ...

Q 5. Minimum water elevation on upstream side of a diversion weir's Spillway is $400\mathrm{m}$. a) The minimum flowrate is $94{\mathrm{m}}^3/\mathrm{s}$, thalweg elevation on upstream side of the spillway is $394\mathrm{m}$, and effective crest length is $50\mathrm{m}$. Please find the height of spillway. $\left({\mathrm{C}}_{\min }=1.88\right)$ b) The maximum flow rate is $430.86{\mathrm{m}}^3/\mathrm{s}$, so please calculate the maximum spillway head, by neglecting approach velocity on upstream side. $\left({\mathrm{C}}_{\max }=2.18\right)$ c) By obtaining maximum spillway head and maximum flowrate as Project Spillway Head and Project Flowrate, compute the water depth at the toe of structure, average velocity value and Froude Number on this zone, (Assume effective crest length and stilling basin channel width are the same.) d) By calculating the downstream side depth ( ${\mathrm{y}}_2)$ of hydraulic jump, determine the stilling basin type and its dimensions. $\mathrm{Q}=\mathrm{C}\ast \mathrm{B}\ast {\mathrm{h}}^{1.5};{\mathrm{y}}_2=\frac{{\mathrm{y}}_1}{2}\ast \left[\sqrt{1+8\ast {\mathrm{N}}_{\mathrm{Fr}1}^2}-1\right]$