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(Solved): Q. 59 For a random variable \mu =100P=\alpha x>=110xP(90<=x<=110)1-2\alpha 1-\alpha 1-(\alp ...


Q. 59 For a random variable

\mu =100P=\alpha x>=110xP(90<=x<=110)1-2\alpha 1-\alpha 1-(\alpha )/(2)2\alpha


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