Home /
Expert Answers /
Mechanical Engineering /
question-2-35-marks-the-force-f-acting-in-a-constant-direction-on-the-block-of-mass-m-has-a-m-pa842

Question 2 ( 35 marks) The force

`F`

, acting in a constant direction on the block of mass

`M`

, has a magnitude which varies with the position

`x`

of the block. When

`x=0`

, the block is moving to the right at speed

`v_(0)`

. The coefficient of kinetic friction between the block and surface is

`\mu _(k)`

, as shown in Figure 2. (Hint: use work and energy principle) Given:

```
M=20kg,c=3
v_(1)=5(m)/(s),d=4
v_(0)=2(m)/(s),k=50(N)/(m)2
\mu _(k)=0.3,g=9.81(m)/(s)2
```

a) Draw free body diagram for the system. (5 marks) b) Prove that

`N_(B)=Mg+((c)/(\sqrt(c^(2)+d^(2))))kx^(2)`

. (5 marks) c) Determine how far the block slides before its velocity becomes

`v_(1)`

. (10 marks) d) Determine the speed of the block after it slides a distance

`s=3m`

. (10 marks) e) What happen if we consider static friction in the system. (5 marks)