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(Solved): Question 2 ( 35 marks) The force F, acting in a constant direction on the block of mass M, has a m ...
Question 2 ( 35 marks) The force
F, acting in a constant direction on the block of mass
M, has a magnitude which varies with the position
xof the block. When
x=0, the block is moving to the right at speed
v_(0). The coefficient of kinetic friction between the block and surface is
\mu _(k), as shown in Figure 2. (Hint: use work and energy principle) Given:
M=20kg,c=3
v_(1)=5(m)/(s),d=4
v_(0)=2(m)/(s),k=50(N)/(m)2
\mu _(k)=0.3,g=9.81(m)/(s)2a) Draw free body diagram for the system. (5 marks) b) Prove that
N_(B)=Mg+((c)/(\sqrt(c^(2)+d^(2))))kx^(2). (5 marks) c) Determine how far the block slides before its velocity becomes
v_(1). (10 marks) d) Determine the speed of the block after it slides a distance
s=3m. (10 marks) e) What happen if we consider static friction in the system. (5 marks)
