(Solved): Question 3 10 Figure below shows a parallel-plate capacitor of plate area A and plate separation d ...

Question 3 10 Figure below shows a parallel-plate capacitor of plate area A and plate separation d. A potential difference Vo is applied between the plates by connecting a battery between them. The battery is then disconnected, and a dielectric slab of thickness b and dielectric constant k is placed between the plates as shown. Assume A = 125 cm², d = 1 cm, Vo = 90 V, b=0.80 cm, and k = 5 (a) What is the capacitance Co before the dielectric slab is inserted? (b) What free charge appears on the plates? (c) What is the electric field Eo in the gaps between the plates and the dielectric slab? (d) What is the electric field E, in the dielectric slab? (e) What is the potential difference between the plates after the slab has been introduced? (f) What is the capacitance with the slab in place? +} Gaussian surface -q " & + Gaussian surface Hint: Gaussian surfaces I and II can be used to calculate the electric fields