QUESTION 4 Falling flat on the feet from a height of 45.9 cm is considered to be dangerous for a
67-kg
person as the stress of impact force reaches bone rupture strength equal
10^(9)(dyn)/(cm^(2))
. If area of impact is
2cm^(2)
, what is the average impact time measured in milliseconds? Present only numerical portion of your answer.
1dyn=(g\times cm)/(sec^(2))=(10^(-3)(kg)\times 10^(-2)(m))/(sec^(2))=10^(-5)N

Question

QUESTION 4 Falling flat on the feet from a height of 45.9 cm is considered to be dangerous for a

67-kg

person as the stress of impact force reaches bone rupture strength equal

10^(9)(dyn)/(cm^(2))

. If area of impact is

2cm^(2)

, what is the average impact time measured in milliseconds? Present only numerical portion of your answer.

1dyn=(g\times cm)/(sec^(2))=(10^(-3)(kg)\times 10^(-2)(m))/(sec^(2))=10^(-5)N

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